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Re: Plot of Nonlinear function

  • To: mathgroup at smc.vnet.net
  • Subject: [mg40902] Re: Plot of Nonlinear function
  • From: "Bill Bertram" <wkb at ansto.gov.au>
  • Date: Wed, 23 Apr 2003 05:17:33 -0400 (EDT)
  • Organization: Australian Nuclear Science and Technology Organisation
  • References: <b8582c$5pj$1@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

"Jong Choi" <jxc91 at po.cwru.edu> wrote in message
news:b8582c$5pj$1 at smc.vnet.net...
> I want to plot this funcion with theta1 vs. theta2
>
>
> (theta1-pi/2) * Sin[theta1+theta2] - (theta2-pi/2) * (Sin[theta1] +
> Sin[theta1+theta2]) = 0
>
> this function is not linear.
> the values of x axis are theta1 and those of y axis are theta2.
> I think I have to solve this fuction first and then plot.
>

Just a follow-up from my previous posting. If you ContourPlot the
Lefthand-side of your equation in the range {theta1,-Pi, Pi}, {theta2, -Pi,
Pi} you'll see that the function has a saddle point near x = -0.5, y = 0.3.
This makes the method I gave in my previous posting break down in this
region. FindRoot doesn't work too well near saddle points.





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