Re: How to examine x=(x+a)/b
- To: mathgroup at smc.vnet.net
- Subject: [mg40924] Re: [mg40900] How to examine x=(x+a)/b
- From: Bobby Treat <drmajorbob+MathGroup3528 at mailblocks.com>
- Date: Thu, 24 Apr 2003 05:29:04 -0400 (EDT)
- Sender: owner-wri-mathgroup at wolfram.com
Ponder this for various n: Clear[a,b,x] n = 8; Simplify@Nest[(# + a)/b &, x, n] Why is that the right expression, and what happens when n gets large? What if Abs[b] < 1? What if b = 1? What if b = -1? What if Abs[b] > 1? Bobby -----Original Message----- From: Andy <news at andyhemmings.com> To: mathgroup at smc.vnet.net Subject: [mg40924] [mg40900] How to examine x=(x+a)/b Hi I have been asked to examine the following as part of some homework. x=(x+a)/b I know the calculation repeats its self and reaches a point where the input and output numbers are the same, however, i cant explain why and how. Any help or guidance would be appreciated.