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AW: [newbie] can't get the answer

  • To: mathgroup at smc.vnet.net
  • Subject: [mg43133] AW: [mg43117] [newbie] can't get the answer
  • From: Matthias.Bode at oppenheim.de
  • Date: Thu, 14 Aug 2003 05:07:49 -0400 (EDT)
  • Sender: owner-wri-mathgroup at wolfram.com

Hello Promania,

supposing that "97" and "42" are angles in degrees:

Input:
Cosh[Sinh[97/180*Pi]] + Sin[42/180*Pi] + Sinh[Exp[2]]/1
N[%]

Output:
Cosh[Sinh[(97*Pi)/180]] + 
  Sin[(7*Pi)/30] + Sinh[E^2]
816.7019043450655

The division by one "Sinh[Exp[2]]/1" does not change the result and can be
omitted.

Best regards,
Matthias Bode
Sal. Oppenheim jr. & Cie. KGaA
Koenigsberger Strasse 29
D-60487 Frankfurt am Main
GERMANY
Tel.: +49(0)69 71 34 53 80
Mobile: +49(0)172 6 74 95 77
Fax: +49(0)69 71 34 95 380
E-mail: matthias.bode at oppenheim.de
Internet: http://www.oppenheim.de




-----Ursprungliche Nachricht-----
Von: Promania Corasna [mailto:gjgjdt at xs4all.nl]
Gesendet: Mittwoch, 13. August 2003 13:50
An: mathgroup at smc.vnet.net
Betreff: [mg43117] [newbie] can't get the answer


Hello all,

I'm a newbie in using mathematica 5. I've searched over the internet, but I
can't find out how to get the answer to my formula. This is the formula, I
have to calculate:

cosh(sinh(97))+(sin(42)+sinh(e^2))/1

This is the answer of mathematica:

42\ sin + 97\ cosh\ sinh + e\^2\ sinh\)



I just niet a answer from plain number.

Does anybody knows how to do that?

THanks in advance


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