Re: is this a new bug? Mathematicaa 5.0...
- To: mathgroup at smc.vnet.net
- Subject: [mg43203] Re: is this a new bug? Mathematicaa 5.0...
- From: Paul Abbott <paul at physics.uwa.edu.au>
- Date: Tue, 19 Aug 2003 07:53:08 -0400 (EDT)
- Organization: The University of Western Australia
- References: <bhfkcb$6ak$1@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
In article <bhfkcb$6ak$1 at smc.vnet.net>, w1rw1ck at hotmail.com (steven)
wrote:
> Assuming[b > 0 && [Omega] > 0 && b [NotEqual] [Omega] ,
> Integrate[
> (Sin[b t]/(b t)) [ExponentialE]^([ImaginaryI][Omega]t),
> {t, (-[Infinity]), [Infinity]}]])
>
> Out = 0 ( think this should be a "rectangle" function.. )
Since you are computing a Fourier transform, why not use
FourierTransform[Sin[b t]/(b t), t, w]
which does, indeed, give you what you are after (and quickly too).
Cheers,
Paul
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