Re: Re: a first-time user question

*To*: mathgroup at smc.vnet.net*Subject*: [mg39402] Re: [mg39376] Re: a first-time user question*From*: Jan Mangaldan <hokenjan at yahoo.com>*Date*: Fri, 14 Feb 2003 03:18:18 -0500 (EST)*Sender*: owner-wri-mathgroup at wolfram.com

Better yet: In[1]:= realCubeRoot[z_]:= Sign[z] Abs[z]^(1/3) In[2]:= Plot[(realCubeRoot[x])^2, {x,-1,0}] Hope this helps. Jan M. (^_^) Nilton Volpato <nilton.volpato at ig.com.br> wrote: Use: Needs["Miscellaneous'RealOnly'"] Plot[x^(2/3), {x,-1,0}] This will work. -- Nilton "Ye Hu" wrote in message news:... > I have a simple (supposedly) question... > > I used the following command to draw a plot, but Mathematica could not run > properly. > > Plot[x^(2/3),{x,-1,0}] > > > I know the problem is about calculating (-1)^(1/3) in mathematica. Although > (-1)^(1/3) = -1, > mathematica tries to calculate it numerically and gives complex results > 0.5+0.8i > How to solve this problem and restrict the solution to be only real numbers? > > Thanks very much.