Re: a first-time user question
- To: mathgroup at smc.vnet.net
- Subject: [mg39449] Re: a first-time user question
- From: "Narasimham G.L." <google.news.invalid at web2news.net>
- Date: Sun, 16 Feb 2003 06:13:42 -0500 (EST)
- References: <200302120852.DAA14779@smc.vnet.net> <b2iav3$1@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
As it has a cusp at x=0, better to write as
Plot[ {(x^2)^(1/3)},{x, -1, 1}];
as roots are reported in counter-clockwise direction
with respect to x-axis in Argand diagram, try
Re[-(1)^(1/3)] and Im[-(1)^(1/3)] to capture the real root.
> As y=x^(2/3) is equivalent to y^3=x^2, you can use:
>
> << 'Graphics`ImplicitPlot`'
>
> ImplicitPlot[y^3 == x^2,
> {x, -1, 1}]
>
> Germán Buitrago A.
> Manizales, Colombia
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- a first-time user question
- From: "Ye Hu" <huye@wharton.upenn.edu>
- a first-time user question