Re: yield to maturity
- To: mathgroup at smc.vnet.net
- Subject: [mg41743] Re: yield to maturity
- From: Paul Abbott <paul at physics.uwa.edu.au>
- Date: Tue, 3 Jun 2003 07:13:27 -0400 (EDT)
- Organization: The University of Western Australia
- References: <bbf34j$q2i$1@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
In article <bbf34j$q2i$1 at smc.vnet.net>, "Jonathan Mann" <mtheory at msn.com> wrote: > I need to solve for r in an equation of the form: > > Sum[I/(1+r)^t, {t,1,n}] + M/(1+r)^n ]==P > > For example's sake, let's say: > > Solve[ Sum[ 45/(1+r)^t ,{t,1,5}] + 1000/(1+r)^5 == 913, r] > > This isn't working out too well. Actually, it is working perfectly! It is giving you exact representations of the 5 solutions to this equation. However, for r > 0, you can use Experimental`CylindricalAlgebraicDecomposition[ Sum[45/(r + 1)^t, {t, 1, 5}] + 1000/(r + 1)^5 == 913 && r > 0, {r}] which gives an _exact_ representation of the solution you are after. If you apply N to this you get N[%] r == 0.06599124150108003 Cheers, Paul -- Paul Abbott Phone: +61 8 9380 2734 School of Physics, M013 Fax: +61 8 9380 1014 The University of Western Australia (CRICOS Provider No 00126G) 35 Stirling Highway Crawley WA 6009 mailto:paul at physics.uwa.edu.au AUSTRALIA http://physics.uwa.edu.au/~paul