Re: Plot a recurrence relation

*To*: mathgroup at smc.vnet.net*Subject*: [mg40176] Re: Plot a recurrence relation*From*: Dr Bob <drbob at bigfoot.com>*Date*: Tue, 25 Mar 2003 03:03:33 -0500 (EST)*References*: <200303240928.EAA28657@smc.vnet.net>*Reply-to*: drbob at bigfoot.com*Sender*: owner-wri-mathgroup at wolfram.com

For instance, a[0] = 6; a[n_] := a[n] = a[#]/(2# - 7) &@(n - 1) ListPlot[a /@ Range[0, 8], PlotRange -> All, PlotJoined -> True, AxesOrigin -> {1, 0}] Bobby On Mon, 24 Mar 2003 04:28:22 -0500 (EST), David <davidol at hushmail.com> wrote: > How can I get mathematica to plot a sequence that's defined recursively > e.g. > > a_0 = 6 > a_(n+1) = a_n / (2n - 7) > > Cheers. > > > > -- majort at cox-internet.com Bobby R. Treat

**References**:**Plot a recurrence relation***From:*"David" <davidol@hushmail.com>