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MathGroup Archive 2003

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Re: Plot a recurrence relation

  • To: mathgroup at smc.vnet.net
  • Subject: [mg40176] Re: Plot a recurrence relation
  • From: Dr Bob <drbob at bigfoot.com>
  • Date: Tue, 25 Mar 2003 03:03:33 -0500 (EST)
  • References: <200303240928.EAA28657@smc.vnet.net>
  • Reply-to: drbob at bigfoot.com
  • Sender: owner-wri-mathgroup at wolfram.com

For instance,

a[0] = 6;
a[n_] := a[n] = a[#]/(2# - 7) &@(n - 1)
ListPlot[a /@ Range[0, 8], PlotRange -> All,
           PlotJoined -> True, AxesOrigin -> {1, 0}]

Bobby

On Mon, 24 Mar 2003 04:28:22 -0500 (EST), David <davidol at hushmail.com> 
wrote:

> How can I get mathematica to plot a sequence that's defined recursively 
> e.g.
>
> a_0 = 6
> a_(n+1) = a_n / (2n - 7)
>
> Cheers.
>
>
>
>



-- 
majort at cox-internet.com
Bobby R. Treat



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