Mathematica 9 is now available
Services & Resources / Wolfram Forums
-----
 /
MathGroup Archive
2003
*January
*February
*March
*April
*May
*June
*July
*August
*September
*October
*November
*December
*Archive Index
*Ask about this page
*Print this page
*Give us feedback
*Sign up for the Wolfram Insider

MathGroup Archive 2003

[Date Index] [Thread Index] [Author Index]

Search the Archive

Re: Plot a recurrence relation

  • To: mathgroup at smc.vnet.net
  • Subject: [mg40188] Re: Plot a recurrence relation
  • From: Jens-Peer Kuska <kuska at informatik.uni-leipzig.de>
  • Date: Tue, 25 Mar 2003 14:47:34 -0500 (EST)
  • Organization: Universitaet Leipzig
  • References: <b5mj14$rsa$1@smc.vnet.net>
  • Reply-to: kuska at informatik.uni-leipzig.de
  • Sender: owner-wri-mathgroup at wolfram.com

Hi,

define

a[0] = 6
a[n_Integer /; n > 0] := a[n] = a[n - 1]/(2(n - 1) - 7)

ListPlot[Table[a[i], {i, 0, 20}]]

Regards
  Jens


David wrote:
> 
> How can I get mathematica to plot a sequence that's defined recursively e.g.
> 
> a_0 = 6
> a_(n+1) = a_n / (2n - 7)
> 
> Cheers.


  • Prev by Date: Re: proper way to manipulate lists?
  • Next by Date: Re: The difference between Needs[ ] & Get[ ]
  • Previous by thread: Re: Plot a recurrence relation
  • Next by thread: List in base 16