Re: HoldForm Question
- To: mathgroup at smc.vnet.net
- Subject: [mg41356] Re: HoldForm Question
- From: Jens-Peer Kuska <kuska at informatik.uni-leipzig.de>
- Date: Fri, 16 May 2003 06:40:17 -0400 (EDT)
- Organization: Universitaet Leipzig
- References: <b9viur$e0i$1@smc.vnet.net>
- Reply-to: kuska at informatik.uni-leipzig.de
- Sender: owner-wri-mathgroup at wolfram.com
Hi,
RelpaceAll[] is not a evaluation and
MatrixForm[
Table[HoldForm[(2*Pi*rr*cc)/8] /. {rr -> r, cc -> c}, {r, 0, 7}, {c,
0, 7}]]
may help you.
Regards
Jens
Dana DeLouis wrote:
>
> Hello. Could someone point me in the right direction on the use of
> Hold? I cannot seem to find a solution.
>
> In this simple table, I would like to first substitute the values of r &
> c, but then not reduce the equation.
>
> MatrixForm[Table[HoldForm[(2*Pi*r*c)/8], {r, 0, 7}, {c, 0, 7}]]
>
> Here, I get a table of all "2 Pi r c / 8"
>
> This is close, but I would like the r's and c's to have the appropriate
> values.
>
> I would like "2 Pi 0 0 / 8", "2 Pi 0 1 / 8"....etc
>
> I have gone thru all the Hold functions without much luck.
> I could not find anything in the achieves either.
>
> InputForm[Names["Hold*"]]
>
> {"Hold", "HoldAll", "HoldAllComplete", "HoldComplete", "Holdfirst",
> "HoldFirst", "HoldForm", "HoldPattern", "HoldRest"}
>
> Thank you very much for your help.
>
> --
> Dana
> Windows XP
> $VersionNumber -> 4.2
> = = = = = = = = = = = = = = = = =