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Re: use of SetDelayed functions in Plot and Solve
*To*: mathgroup at smc.vnet.net
*Subject*: [mg44601] Re: [mg44585] use of SetDelayed functions in Plot and Solve
*From*: Anton Antonov <antonov at wolfram.com>
*Date*: Mon, 17 Nov 2003 03:38:36 -0500 (EST)
*References*: <200311150705.CAA11421@smc.vnet.net>
*Sender*: owner-wri-mathgroup at wolfram.com
Hi,
(1)
In the first, SetDelayed input you use NIntegrate, in the second, Set
input you use Integrate. If you use Integrate in the SetDelayed input
you will get the plot.
NIntegrate is a numerical function, so at the time it is invoked all of
its arguments should be numbers or evaluate to numbers. When you use the
definitions
Clear[s, i, k];
s[t_] := NIntegrate[t^2 - z*Log[t], {z, 0, k[t]}];
i[t_] := D[s[t], t] /. {k[t] -> 2t, k'[t] -> Sin[t]};
the command D[s[t],t] in i[t_] trys to evaluate NIntegrate with a
symbolic variable range. With Integrate, of course, symbolic ranges are
fine.
(2)
As for the Solve part, you can try FindRoot, instead of Solve.
In[1]:=
Clear[s, i];
s[t_] := Integrate[t^2 - z*Log[t], {z, 0, k[t]}];
i[t_] := D[s[t], t] /. {k[t] -> 2t, k'[t] -> Sin[t]};
In[6]:=FindRoot[i[t]==300,{t,1}]
Out[6]={t->8.48795}
Anton Antonov
Wolfram Research, Inc.
Mukhtar Bekkali wrote:
>Why can't I plot the function and find the solution to the equation below
>using SetDelayed functions? Below is just an example, the real functions
>are symbolically non-integrable.
>
>s[t_] :=NIntegrate[t^2 - z*Log[t] , {z, 0, k[t]}]
>i[t_] := D[s[t],t] /. {k[t] ->2t,k'[t]->Sin[t]}
>Plot[i[t], {t, 1, 10}]
>Solve[i[t]==300, t]]
>
>
>All I get is an empty graph because I have "not machine real size numbers"
>and my equation "appears to be solved essentially in non-algebraic way".
>If I rewrite the code using simple Set I get my graph and solutions.
>
>s=Integrate[t^2 - z*Log[t] , {z, 0, k[t]}]
>i=D[s,t] /. {k[t]->2t,k'[t]->Sin[t]}
>Plot[i, {t, 1, 10}]
>Solve[i==300, t]]
>
>Very confused. Thanks, Mukhtar Bekkali
>
>
>
>
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