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Re: Improper integral


poujadej at yahoo.fr (Jean-Claude Poujade) wrote:
> Bonjour le groupe,
>
> I'm not a mathematician and I wonder why Mathematica doesn't return 0
> for this doubly infinite improper integral :
>
> In[1]:=$Version
> Out[1]=4.1 for Microsoft Windows (November 2, 2000)
>
> In[2]:=Integrate[x/(1+x^2),{x,-Infinity,Infinity},PrincipalValue->True]
> Integrate::idiv[...]does not converge[...]
> Out[2]:=Integrate[x/(1+x^2),{x,-Infinity,Infinity},PrincipalValue->True]
>
> maybe it's different with Mathematica 5.0 ?

Unfortunately, version 5 does the same thing.

Here's what you can do to help Mathematica get the principal value:

Limit[Integrate[x/(1+x^2),{x,-a,0}]+Integrate[x/(1+x^2),{x,0,a}],a->Infinity]

That returns 0, as it should.

David


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