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MathGroup Archive 2003

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Re: Plotting functions with undefined values

  • To: mathgroup at smc.vnet.net
  • Subject: [mg43765] Re: Plotting functions with undefined values
  • From: "Bo Le" <bole79 at email.si>
  • Date: Fri, 3 Oct 2003 02:28:50 -0400 (EDT)
  • References: <blgk0b$jb2$1@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

Hi,

You can define your function with the If clause:

f[x_,y_,m_]:=If[y==1-x,0,(m+x+1)/(x+y-1)];

Plot3D[ f[x,y,1],{x,0,1},{y,0,1} ]


"Ronaldo Prati" <rcprati at bol.com.br> wrote in message
news:blgk0b$jb2$1 at smc.vnet.net...
>
> Hello everybody
>
> I'm a new student using mathematica and I couldn't solve my problem by
> myself.
>
> I need to plot the function pos[m_] = (m + x -1)/(x+y-1), where
> 0<=pos<1, x and y are between 0 and 1 but x+y-1!=0. My problem is
> that I could not input this constrain. When plot the function using
> Plot3D, at the region where x+y = 1 several erros of infinith
> expression 1/0 encountred are given. I'm not interested in plotting the
> region where x+1 occurs, but the region where the function has a true
> value (the graphic appers, but with a straigh region where it is undef).
> How can i solve it?
>


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