Re: Plotting functions with undefined values

*To*: mathgroup at smc.vnet.net*Subject*: [mg43765] Re: Plotting functions with undefined values*From*: "Bo Le" <bole79 at email.si>*Date*: Fri, 3 Oct 2003 02:28:50 -0400 (EDT)*References*: <blgk0b$jb2$1@smc.vnet.net>*Sender*: owner-wri-mathgroup at wolfram.com

Hi, You can define your function with the If clause: f[x_,y_,m_]:=If[y==1-x,0,(m+x+1)/(x+y-1)]; Plot3D[ f[x,y,1],{x,0,1},{y,0,1} ] "Ronaldo Prati" <rcprati at bol.com.br> wrote in message news:blgk0b$jb2$1 at smc.vnet.net... > > Hello everybody > > I'm a new student using mathematica and I couldn't solve my problem by > myself. > > I need to plot the function pos[m_] = (m + x -1)/(x+y-1), where > 0<=pos<1, x and y are between 0 and 1 but x+y-1!=0. My problem is > that I could not input this constrain. When plot the function using > Plot3D, at the region where x+y = 1 several erros of infinith > expression 1/0 encountred are given. I'm not interested in plotting the > region where x+1 occurs, but the region where the function has a true > value (the graphic appers, but with a straigh region where it is undef). > How can i solve it? >