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MathGroup Archive 2003

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Negation of Negation wanted

  • To: mathgroup at
  • Subject: [mg44023] Negation of Negation wanted
  • From: Thomas Gutzler <gutzler at>
  • Date: Sat, 18 Oct 2003 03:12:15 -0400 (EDT)
  • Organization: University of Karlsruhe, Germany
  • Sender: owner-wri-mathgroup at


Assuming f(x) = x1 && x2

Is there a way to get !f(!x), which is:
!(!x1 && !x2) = x1 || x2
without copy&paste and manually change it?


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