[Date Index]
[Thread Index]
[Author Index]
Re: Problem with Sum
*To*: mathgroup at smc.vnet.net
*Subject*: [mg44037] Re: [mg44004] Problem with Sum
*From*: Andrzej Kozlowski <akoz at mimuw.edu.pl>
*Date*: Sat, 18 Oct 2003 03:12:45 -0400 (EDT)
*Sender*: owner-wri-mathgroup at wolfram.com
On Friday, October 17, 2003, at 06:14 PM, Mariusz Jankowski wrote:
> Hello, can someone explain the following result:
>
> Sum[(-1)^m * (DiscreteDelta[1 - 2*m] - 2*DiscreteDelta[1 + 3*m]), {m,
> -Infinity, Infinity}]
>
> gives I + 2 (-1)^(2/3)
>
> Shouldn't the sum evaluate to zero, since for any value of m the
> summand is identically zero. Note that
>
> Sum[(-1)^m * (DiscreteDelta[1 - 2*m] - 2*DiscreteDelta[1 + 3*m]), {m,
> -10, 10}] returns 0, as expected.
>
> This looks like a bug, is it?
>
> Thanks, Mariusz
>
>
>
>
Hello Mariusz,
It is difficult to say if such things should be considered bugs or not,
since the answer does have a sensible interpretation. It is possible to
interpret
In[1]:=
Sum[(-1)^m*(DiscreteDelta[1 - 2*m] -
2*DiscreteDelta[3*m + 1]), {m, -Infinity, Infinity}]
Out[1]=
I + 2*(-1)^(2/3)
as meaning the same as:
In[2]:=
Integrate[(-1)^x*(DiracDelta[x - 1/2] -
2*DiracDelta[x + 1/3]), {x, -Infinity, Infinity}]
Out[2]=
I + 2*(-1)^(2/3)
Of course if this is indeed what is done one would expect it to be
documented somewhere!
Andrzej Kozlowski
Yokohama, Japan
http://www.mimuw.edu.pl/~akoz/
http://platon.c.u-tokyo.ac.jp/andrzej/
Prev by Date:
**Re: Bug in ReplaceAll and ReplaceRepeated?**
Next by Date:
**RE: Bug in ReplaceAll and ReplaceRepeated?**
Previous by thread:
**Problem with Sum**
Next by thread:
**RE: RE: Problem with Sum**
| |