Re: bug in IntegerPart ?
- To: mathgroup at smc.vnet.net
- Subject: [mg47850] Re: bug in IntegerPart ?
- From: ancow65 at yahoo.com (AC)
- Date: Wed, 28 Apr 2004 06:56:52 -0400 (EDT)
- References: <email@example.com>
- Sender: owner-wri-mathgroup at wolfram.com
Bill Rowe <readnewsciv at earthlink.net> wrote in message news:<c6l8dj$isr$1 at smc.vnet.net>...
> On 4/26/04 at 2:41 AM, ancow65 at yahoo.com (AC) wrote:
> >"DrBob" <drbob at bigfoot.com> wrote in message
> >news:<c6g015$4lk$1 at smc.vnet.net>...
> >>There's NO reason to be puzzled. 1.65 and 1.3 can't be represented
> >>exactly in binary, so of course their difference may not be exact,
> >>either. Hence the division problems have different numerators.
> >Your 'explanation' makes no sense whatsoever. Mathematica's binary
> >representations of 1.65-1.3 and 0.35 are the same. That can be seen
> >by comparing BaseForm[1.65 - 1.3, 2] with BaseForm[0.35,2]
> BaseForm isn't doing what you think and will not show the difference. BaseForm controls only the display of a number. By default Mathematica displays a number to 6 significant digits. Both 1.65 - 1.3 and .35 are the same to 6 significant digits. Consequently, these will display the same when using BaseForm.
> To see the difference use RealDigits or FullForm. Both of these clearly show the difference between 1.65 - 1.3 and .35.
The decimal numbers (1.65 - 1.3) and .35 are identical. The way
Mathematica performs subtraction makes them different.
> >(n = 2^^0.010110011001100110011 )
> > => 0.350000
> Right, here you've inputed a number accurate to 6 significant digits. So, Mathematica displays 6 significant digits
When I type 0.35, Mathematica assumes the machine precision.
% // N
Isn't that natural to expect similar for binary numbers?
> > Notice the unussual display of trailing zeros.
> No, not unusual. Exactly as it should be. If I input 6 significant digits as
> .35`6, I expect Mathematica to display 6 significant digits with the default settings.
And, I guess, you don't see any problems with these three inputs
producing the same output 0.35.
> >Additionally, a completely legitimate expression
> >2^^BaseForm[0.35`, 2]
> >produces a syntax error message.
> The expression 2^^BaseForm[0.35, 2] isn't a legitimate expression. BaseForm puts a wrapper on the expression to control display. That is Head at BaseForm[0.35, 2] is BaseForm, not a sequence of binary digits.
BaseForm[0.35, 2] might be wrong as argument for 2^^#& but still it is
not a syntax error. Would you agree that the following expression
(which also generates a syntax error) is legitimate?
fun := 2^^# &
What about this syntax error?
In better design 2^^BaseForm[0.35, 2] should return 0.35` or at
minimum unchanged expression.
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