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Re: ReadListBinary question


Thanks for the responses! -- I found the quickest way was to include
"Evaluate[nval]" in the call, which seemed to work well.

--j


On 8/4/04 8:10 AM, in article cequ9f$k24$1 at smc.vnet.net, "Jonathan
Greenberg" <greenberg at ucdavis.edu> wrote:

> Is there any reason why ReadListBinary[stream,type,n] doesn't let me use a
> variable for "n" (e.g. If I set nval=5, and ReadListBinary[stream,type,nval]
> -- it won't work)?  Are there any workarounds for this?
> 
> --j
> 


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