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MathGroup Archive 2004

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Re: Invoking a function using full package name fail, but works without full package name

  • To: mathgroup at smc.vnet.net
  • Subject: [mg52586] Re: Invoking a function using full package name fail, but works without full package name
  • From: "Jens-Peer Kuska" <kuska at informatik.uni-leipzig.de>
  • Date: Fri, 3 Dec 2004 03:53:46 -0500 (EST)
  • Organization: Uni Leipzig
  • References: <comg11$5ps$1@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

Hi,
it is so, because the ImageProcessing calls an other package
for the data import and ImageRead[] is implemented in
the ImageProcessing`ImageData` package and it stand in this context.
So if you "to know where each function is comming from" you
have to *know* where thie function come from.

Regards
  Jens

"nospam nospam" <nospam_please at nospam.com> schrieb im Newsbeitrag 
news:comg11$5ps$1 at smc.vnet.net...
> Hello;
>
> In my code, I usually like to add the package name to the
> function name to know where each function is comming from.
> (A sort of self documenting the code)
>
> Now I found this to cause a problem with this Mathematica
> package.
>
> This is an example
>
> << ImageProcessing`
> img = ImageProcessing`ImageRead["test.gif"];
> Show[Graphics[img]];
>
> The above gives an error
>
> Graphics::gprim: ImageProcessing`ImageRead[test.gif] was encountered \
> where a Graphics primitive or directive was expected
>
> BUT when I do this:
>
> img = ImageRead["test.gif"];
> Show[Graphics[img]];
>
> Then it works.
>
> This completely destroyes my naming convention of using full
> package names in my code.
>
> any idea why this is so? It seems to work ok with another user
> package I tried, but not this one??
>
> thanks,
> --nospam
>
>
> 



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