Re: fullsimplify problem
- To: mathgroup at smc.vnet.net
- Subject: [mg52923] Re: [mg52908] fullsimplify problem
- From: Andrzej Kozlowski <akoz at mimuw.edu.pl>
- Date: Fri, 17 Dec 2004 05:18:33 -0500 (EST)
- Sender: owner-wri-mathgroup at wolfram.com
What do you mean by " incorrect"? It's correct and it's primary school maths. ( - a / b^2) = = ( + a / b^2) -> (2 a / b^2)==0 -> (a/b)*(2/b)==0 -> (a/b)==0. ???????? Andrzej Kozlowski On 16 Dec 2004, at 17:41, symbio wrote: > Given ( - a / b^2) = = ( + a / b^2), it can be written as (-2 a / > b^2), but > when I use FullSimplify on that equation, I get the incorrect result ( > a / > b ) = = 0. How is this possible? > > In[2]:= > -a/b^2 == a/b^2 > % // FullSimplify > Out[2]= > \!\(\(-\(a\/b\^2\)\) == a\/b\^2\) > Out[3]= > \!\(a\/b == 0\) > > In[5]:= > -2a/b^2 == 0 // FullSimplify > Out[5]= > \!\(a\/b == 0\) >