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MathGroup Archive 2004

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Re: All Factors of a number

  • To: mathgroup at
  • Subject: [mg53047] Re: All Factors of a number
  • From: "Ray Koopman" <koopman at>
  • Date: Tue, 21 Dec 2004 05:19:33 -0500 (EST)
  • References: <cq6e8m$2rk$>
  • Sender: owner-wri-mathgroup at

Ulrich Sondermann wrote:
> Following is a test code that I am trying to get down to a set of
> instructions that will allways put all of the factors of a number in
a table
> or list.
> bt contains all of the factors if I multiply each list entry, however
> cannot accomplish that with a single line, as an example I have
broken into
> the three lists needed for this example. The results of each
"Times@@" is
> what I am after all placed into one table. All of my attempts have
> disasterous, I am new to Mathematica and could do this with nested
loops in
> any programming language, but this has me stumped.
> Thanx!
> <<DiscreteMath`Combinatorica`
> bt=Table[KSubsets[{1,2,3,5},a],{a,3}]
> ,3,5},{2,3,5}}}
> bt1=bt[[1,All]]
> {{1},{2},{3},{5}}
>  Table[Times@@bt1[[a]],{a,4}]
> {1,2,3,5}
> bt2=bt[[2,All]]
> {{1,2},{1,3},{1,5},{2,3},{2,5},{3,5}}
> Table[Times@@bt2[[a]],{a,6}]
> {2,3,5,6,10,15}
> bt3=bt[[3,All]]
> {{1,2,3},{1,2,5},{1,3,5},{2,3,5}}
> Table[Times@@bt3[[a]],{a,4}]
> {6,10,15,30}

In[9]:= Map[Map[Times@@#&,#]&,bt]
Out[9]= {{1,2,3,5},{2,3,5,6,10,15},{6,10,15,30}}

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