Services & Resources / Wolfram Forums
-----
 /
MathGroup Archive
2004
*January
*February
*March
*April
*May
*June
*July
*August
*September
*October
*November
*December
*Archive Index
*Ask about this page
*Print this page
*Give us feedback
*Sign up for the Wolfram Insider

MathGroup Archive 2004

[Date Index] [Thread Index] [Author Index]

Search the Archive

Re: Coefficients of previous result

  • To: mathgroup at smc.vnet.net
  • Subject: [mg53115] Re: [mg53096] Coefficients of previous result
  • From: Bob Hanlon <hanlonr at cox.net>
  • Date: Fri, 24 Dec 2004 05:59:02 -0500 (EST)
  • Reply-to: hanlonr at cox.net
  • Sender: owner-wri-mathgroup at wolfram.com

Use Rationalize

expr = (1.+2.x+2.x^2+2.x^3)/(1.+2.x+2.x^2);

expr=Rationalize[expr]

(2*x^3 + 2*x^2 + 2*x + 1)/(2*x^2 + 2*x + 1)


Bob Hanlon

> 
> From: Milind Gupta <milind.gupta at gmail.com>
To: mathgroup at smc.vnet.net
> Date: 2004/12/23 Thu AM 07:58:51 EST
> To: mathgroup at smc.vnet.net
> Subject: [mg53115] [mg53096] Coefficients of previous result
> 
> The result of my previous step is something like this:
> 
> expr =    1. + 2. x + 2. x^2 +  2. x^3
>             -----------------------------------------
>                1. + 2. x + 2. x^2
> 
>    But I need it to be like this:
> 
> 
> expr =    1 + 2 x + 2 x^2 +  2 x^3
>             -----------------------------------------
>                1 + 2 x + 2 x^2
> 
> so that I can use it with another function properly. Is there any way
> to do that?
> 
> Milind
> 
> 


  • Prev by Date: Re: Minors
  • Next by Date: Re: Coefficients of previous result
  • Previous by thread: Re: Coefficients of previous result
  • Next by thread: Re: Coefficients of previous result