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Re: When/why is Denominator[p/q] != q?
*To*: mathgroup at smc.vnet.net
*Subject*: [mg46017] Re: When/why is Denominator[p/q] != q?
*From*: bobhanlon at aol.com (Bob Hanlon)
*Date*: Tue, 3 Feb 2004 03:20:47 -0500 (EST)
*References*: <bvla64$83$1@smc.vnet.net>
*Sender*: owner-wri-mathgroup at wolfram.com
q is not equal to Denominator[p/q]. In Denominator[p/q] the argument p/q is
evaluated before the Denominator is extracted. For example,
q=6; Table[{p, p/q, Denominator[p/q]},{p,q-1}]
{{1, 1/6, 6}, {2, 1/3, 3}, {3, 1/2, 2}, {4, 2/3, 3}, {5, 5/6, 6}}
Bob Hanlon
In article <bvla64$83$1 at smc.vnet.net>, relishguy at pluggedin.org (Relishguy)
wrote:
<< I ran this code (from the "Tour of Mathematica" in the Book ):
(* -------------------------------- *)
g6 = Flatten[Table[Point[{p / q, Denominator[p/q]}], {q, 100}, {p, q -
1}]];
(* same code with q instead of Denominator[p/q] *)
g5 = Flatten[Table[Point[{p / q, q }], {q, 100}, {p, q - 1}]];
Show[Graphics[g5, Frame -> True]]
Show[Graphics[g6, Frame -> True]]
(* -------------------------------- *)
For some reason the graphs are not identical. Can anyone point me to
the reason for this?
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