RE: matrix operations
- To: mathgroup at smc.vnet.net
- Subject: [mg46343] RE: [mg46329] matrix operations
- From: "David Park" <djmp at earthlink.net>
- Date: Mon, 16 Feb 2004 08:59:46 -0500 (EST)
- Sender: owner-wri-mathgroup at wolfram.com
Paolo,
The wonders of functional programming! Here's an example.
mat = Array[x, {4, 4}]
Partition[mat, 2, 1]
(answer = #2 - #1 & @@@ %) // MatrixForm
@@@ is the Apply function, mapped onto the first level of mat. #2 - #1& is a
pure function that subtracts the second argument from the first argument.
David Park
djmp at earthlink.net
http://home.earthlink.net/~djmp/
-----Original Message-----
From: paolo tarpanelli [mailto:tarpanelli at libero.it]
To: mathgroup at smc.vnet.net
Subject: [mg46343] [mg46329] matrix operations
If I have a matrix
a={x[[1,1]],x[[1,2]],...,x[[1,n]]}
{x[[2,1]],x[[2,2]],...,x[[2,n]]}
.
.
.
{x[[m,1]],x[[m,2]],...,x[[m,n]]}
how can I compute the difference between any element and the previous for
each column :
aa={x[[2,1]]-x[[1,1]], x[[2,2]]-x[[1,2]],...,x[[2,n]]-x[[1,n]]}
{x[[3,1]]-x[[2,1]], x[[3,2]]-x[[2,2]],...,x[[3,n]]-x[[2,n]]}
.
.
.
{x[[m,1]]-x[[m-1,1]],x[[m,2]]-x[[m-1,2]],...,x[[m,n]]-x[[m-1,n]]}
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I built this code but it does not work
r=Array[0,{m,n}]
For[j=1,j=n,j++
r[[i,j]]=Table[a[[i+1,j]]-a[[i,j]],{i,1,m-1,1}]]
thanks
Paolo
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