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Re: Solve or LinearSolve or ...?
*To*: mathgroup at smc.vnet.net
*Subject*: [mg46382] Re: [mg46347] Solve or LinearSolve or ...?
*From*: Daniel Lichtblau <danl at wolfram.com>
*Date*: Mon, 16 Feb 2004 23:42:15 -0500 (EST)
*Sender*: owner-wri-mathgroup at wolfram.com
Scott Morrison wrote:
> Hi,
>
> I'm trying to write a function to calculate coefficients in a basis;
> for example
>
> FindCoefficients[{f[a,a],f[a,b],f[b,a],f[b,b]}, f[a,a]+(1/2)f[b,a],
> _f]
>
> should produce {1,0,1/2,0}. The third argument there means `assuming
> all objects matching _f are linearly independent'. More difficult, it
> should produce
>
> FindCoefficients[{f[a]+f[b],f[a]-f[b]},f[a], _f] == {1/2,1/2}.
>
> And finally, it should work with rational functions as coefficients,
> not just numbers, and it should run fast enough to be useful with
> bases with thousands of elements. :-)
>
> I've spent quite some time trying to write something like this, and
> I'm finding it really difficult! I can't seem to use LinearSolve in
> any way -- it seems to trip up when I use rational functions as
> coefficients. I've been trying to work around Solve, but the only
> things that work are glacial in pace!
>
> Any ideas or suggestions? I'd be happy to post some of my attempts if
> they'd be helpful in explaining what I'm trying to do, but mostly I'm
> too embarrassed by them :-)
>
> Scott Morrison
Here is one method that should be reasonably efficient.
findCoefficients[ll_List, expr_, varhead_] := Module[
{cc, coeffs, newexpr, vars, eqns},
coeffs = Array[cc,Length[ll]];
newexpr = coeffs.ll - expr;
vars = Cases[Variables[{ll,expr}], varhead];
eqns = Thread[Map[D[newexpr,#]&, vars] == 0];
coeffs /. First[Solve[eqns,coeffs]]
]
In[34]:= InputForm[findCoefficients[{f[a,a],f[a,b],f[b,a],f[b,b]},
f[a,a]+(1/2)f[b,a], _f]]
Out[34]//InputForm= {1, 0, 1/2, 0}
In[35]:= InputForm[findCoefficients[{f[a]+f[b],f[a]-f[b]},f[a], _f]]
Out[35]//InputForm= {1/2, 1/2}
If this is slow on examples of interest then you may want to post
further information describing such examples.
Daniel Lichtblau
Wolfram Research
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