Re: Re: Nasty bug in Integrate (version 5.0)

*To*: mathgroup at smc.vnet.net*Subject*: [mg45968] Re: [mg45958] Re: Nasty bug in Integrate (version 5.0)*From*: Andrzej Kozlowski <akoz at mimuw.edu.pl>*Date*: Sat, 31 Jan 2004 05:20:31 -0500 (EST)*References*: <200401281019.FAA18530@smc.vnet.net> <bvapk6$aat$1@smc.vnet.net> <200401300917.EAA05062@smc.vnet.net>*Sender*: owner-wri-mathgroup at wolfram.com

But then if you are going to use it only for problems that are trivial to do by hand what is the point of using it at all? Computers are supposed to be good at computing, we are supposed to be good at thinking. Andrzej On 30 Jan 2004, at 10:17, Bobby R. Treat wrote: > The only reason we know the answer is wrong is BECAUSE it's trivial by > hand. It makes no sense to trust Mathematica for problems that are too > hard to > check. > > Bobby > > Andrzej Kozlowski <akoz at mimuw.edu.pl> wrote in message > news:<bvapk6$aat$1 at smc.vnet.net>... >> Mathematica seems to get lost in the large number of checks that it >> attempts to perform to find the exact conditions (in the complex >> plane) for the convergence of this integral. Even if a and b are >> assumed to be real there is a problem that 0 may lie in between them. >> Only in the case when you specify that the limits are both positive or >> both negative you get the correct answers because Mathematica can >> quickly deal with this problem. >> If you really want to see how much checking Mathematica attempts to do >> just evaluate: >> >> Trace[Integrate[1/x + x^c, {x, a, b}], TraceInternal->True] >> >> and be prepared to wait and obtain a huge output. >> >> Anyway, this is clearly a bug. However, it is in general a good idea >> not to ask a computer program to do what is trivial to do by hand, >> which in this case means evaluating a definite rather than an >> indefinite integral. Note that >> >> >> Integrate[1/x + x^c, x] >> >> x^(c + 1)/(c + 1) + Log[x] >> >> and the answer is obtained instantly. If this is what you really were >> after (you can substitute in the limits for example by using: >> >> >> Subtract @@ (Integrate[1/x + x^c, x] /. x -> #1 & ) /@ {b, a} >> >> >> -(a^(c + 1)/(c + 1)) - Log[a] + Log[b] + b^(c + 1)/(c + 1) >> >> >> Of course this now makes sense only under certain conditions on a,b >> and >> c which you now have to determine yourself. >> >> >> On 28 Jan 2004, at 11:19, Math User wrote: >> >>> Hi, >>> >>> Sorry if this has been discussed before. Could anyone explain why >>> Mathematica 5.0 is ignoring the term 1/x in the first and second >>> answers? >>> >>> Thanks! >>> >>> >>> In[1]:= Integrate[1/x + x^c, {x, a, b}] >>> >>> Out[1]= (-a^(1 + c) + b^(1 + c))/(1 + c) >>> >>> In[2]:= Integrate[1/x + x^c, {x, a, b}, Assumptions -> {Element[a, >>> Reals], Element[b, Reals]}] >>> >>> Out[2]= (-a^(1 + c) + b^(1 + c))/(1 + c) >>> >>> In[3]:= Integrate[1/x + x^c, {x, a, b}, Assumptions -> {a > 0, b > >>> 0}] >>> >>> Out[3]= (-a^(1 + c) + b^(1 + c))/(1 + c) + Log[b/a] >>> >>> > >

**References**:**Nasty bug in Integrate (version 5.0)***From:*mathuser7@hotmail.com (Math User)

**Re: Nasty bug in Integrate (version 5.0)***From:*drbob@bigfoot.com (Bobby R. Treat)

**Re: Simplifying a second order eq. system tests=PRIORITY_NO_NAME version=2.55**

**Re: Re: Nasty bug in Integrate (version 5.0)**

**Re: Nasty bug in Integrate (version 5.0)**

**Re: Re: Nasty bug in Integrate (version 5.0)**