Re: ArcCos[x] with x > 1
- To: mathgroup at smc.vnet.net
- Subject: [mg49343] Re: ArcCos[x] with x > 1
- From: koopman at sfu.ca (Ray Koopman)
- Date: Thu, 15 Jul 2004 07:00:06 -0400 (EDT)
- References: <cd35vb$qd5$1@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
jaegerm at ibmt.fhg.de wrote in message news:<cd35vb$qd5$1 at smc.vnet.net>... > [...] Given is a cube of side length a (or, let's say, 1). What is > the mean distance of the cube's centre point to its surface. > Obviously, the result is between a / 2 (the distance to any of the six > centres of the six faces) and a / Sqrt[2] (the distance to any of the > eight corners). Sure, that problem can easily be reduced. Think that > sounds like a simple integration on kindergarden level? So did I. But > I soon got the impression I was wrong. Maybe because the distance from the centre to any corner is Sqrt[(a/2)^2 + (a/2)^2 + (a/2)^2] = (a/2)*Sqrt[3]? :)