RE: Diophantic Equations with Constraints
- To: mathgroup at smc.vnet.net
- Subject: [mg49483] RE: [mg49443] Diophantic Equations with Constraints
- From: "Florian Jaccard" <florian.jaccard at eiaj.ch>
- Date: Thu, 22 Jul 2004 02:44:47 -0400 (EDT)
- Reply-to: <florian.jaccard at eiaj.ch>
- Sender: owner-wri-mathgroup at wolfram.com
Hello !
You can use Reduce :
In[1]:=
Reduce[3*x + 2*y - z == 14 && 3 <= x <= 8 &&
0 <= y <= 12 && 1 <= z <= 9, {x, y, z}, Integers]
Out[1]=
y == 0 && z == 1 && x == 5 || y == 0 && z == 4 &&
x == 6 || y == 0 && z == 7 && x == 7 ||
y == 1 && z == 3 && x == 5 || y == 1 && z == 6 &&
x == 6 || y == 1 && z == 9 && x == 7 ||
y == 2 && z == 2 && x == 4 || y == 2 && z == 5 &&
x == 5 || y == 2 && z == 8 && x == 6 ||
y == 3 && z == 1 && x == 3 || y == 3 && z == 4 &&
x == 4 || y == 3 && z == 7 && x == 5 ||
y == 4 && z == 3 && x == 3 || y == 4 && z == 6 &&
x == 4 || y == 4 && z == 9 && x == 5 ||
y == 5 && z == 5 && x == 3 || y == 5 && z == 8 &&
x == 4 || y == 6 && z == 7 && x == 3 ||
y == 7 && z == 9 && x == 3
Greetings
F.Jaccard
-----Message d'origine-----
De : Michael S. [mailto:MikeSuesserott at t-online.de]
Envoyé : mar., 20. juillet 2004 13:54
À : mathgroup at smc.vnet.net
Objet : [mg49443] Diophantic Equations with Constraints
Hi group,
given an equation like
3x + 2y - z == 148
with
x in Range[3,8],
y in Range[0,12],
z in Range[1,9],
what would be the best way to solve this?
Thanks and best regards,
Michael