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Re: Re: limits on symbol eigenvalues?
On 5 Jun 2004, at 20:18, Curt Fischer wrote: > Uwe Brauer wrote: >> Hello >> >> I just started using mathematica. When I tried to calculate the >> symbolic eigenvalues of a 16x16 matrix mathematica told me it couldn't >> >> Is there a restriction? > > I think Mathematica couldn't do it because it is impossible to find the > symbolic roots to a sixteenth order polynomial, in general. > > -- > Curt Fischer > > > Actually this is not quite true. It is certianly possible to find symbolic roots of a polynomial od degree 16 or higher and Mathematica can do it. (Just try it yourself). What is not possible, in general, is to express this solution in terms of radicals, but that is quite a different issue, unrelated to this problem. The original question can't be answered with so little information. Andrzej Kozlowski