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RE: faster sublist checking

  • To: mathgroup at
  • Subject: [mg48675] RE: [mg48640] faster sublist checking
  • From: "Ellis, George" <George.Ellis at Cognos.COM>
  • Date: Thu, 10 Jun 2004 02:43:16 -0400 (EDT)
  • Sender: owner-wri-mathgroup at
  • Thread-topic: [mg48640] faster sublist checking


I would suggest:

a = Range[3, 5];
b = Range[1, 10];
Intersection[a, b] == a

Unless I misunderstand what you want?



-----Original Message-----
From: giorgio borghi [mailto:gimbo20032003 at] 
To: mathgroup at
Subject: [mg48675] [mg48640] faster sublist checking

which is the faster implementantion of function that checks if a list A
is a sublist of B. es:  A={3,4,5} B={1,2,3,4,5,6,7} gives True? 
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