[Date Index]
[Thread Index]
[Author Index]
Integration error in 5.0?
*To*: mathgroup at smc.vnet.net
*Subject*: [mg48728] Integration error in 5.0?
*From*: "Richard Ollerton" <r.ollerton at uws.edu.au>
*Date*: Fri, 11 Jun 2004 03:53:37 -0400 (EDT)
*Sender*: owner-wri-mathgroup at wolfram.com
I used Mathematica 5.0 (Windows 2000) to find the value of an integral
representing the volume under the sphere x^2 + y^2 + z^2 = 4 and above the
cone z = 2 Sqrt(x^2 + y^2) (just to check my own calculation). The value
given for the analytical calculation in Cartesian coordinates using
Integrate is incorrect while exactly the same integral using NIntegrate is
correct as confirmed by the equivalent version in spherical coordinates.
4Integrate[1,{x,0,2/Sqrt[5]},{y,0,Sqrt[4/5-x^2]},{z,2Sqrt[x^2+y^2],Sqrt[4-x^
2-y^2]}]
gives -32Pi/(3Sqrt[5])
while
4NIntegrate[1,{x,0,2/Sqrt[5]},{y,0,Sqrt[4/5-x^2]},{z,2Sqrt[x^2+y^2],Sqrt[4-x
^2-y^2]}]
gives 1.76889
The equivalent in spherical is correct:
Integrate[r^2 Sin[p],{t,0,2Pi},{p,0,ArcTan[1/2]},{r,0,2}]
gives 16(5-2Sqrt[5])Pi/15
with
N[%]
1.76889
Has this been noticed previously?
Richard Ollerton
Prev by Date:
**Query the paste buffer for coordinates in a graphic**
Next by Date:
**Re: Creating combinations from a group of sets**
Previous by thread:
**Query the paste buffer for coordinates in a graphic**
Next by thread:
**Re: Integration error in 5.0?**
| |