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Re: Controlling function arguments


HI,
    Because x is a list,so And@@ is applied to every member of x to make 
sure every elment is number.
Daohua

On Thu, 17 Jun 2004, Virgil Stokes wrote:

> I found the following Mathematica code:
>
>  NumberVectorQ[x_] := VectorQ[x] && And @@ NumberQ /@ x;
>  functionx[k_Integer?Positive, v_?NumberVectorQ, w_?NumberVectorQ,
> q_?NumberVectorQ] := .....
>
> where, I have left out the body of this function (functionx). What does
> the first line actually accomplish?
>
> --V. Stokes
>
>
>
>


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