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Re: solving for variable and then get these e's..?
*To*: mathgroup at smc.vnet.net
*Subject*: [mg46931] Re: solving for variable and then get these e's..?
*From*: Gregor Pfyffer <g.pfyffer at oma.be>
*Date*: Tue, 16 Mar 2004 19:54:56 -0500 (EST)
*References*: <c33de2$ftc$1@smc.vnet.net>
*Sender*: owner-wri-mathgroup at wolfram.com
I found your error! You don't assign a random value to the variable e
you define in In[270], but therfore you twice dfine a value to d ! I
assume this to be a copy-paste error. ;-))
Kind regards
Gregor
sean kim wrote:
> Hello Group.
>
> I was playing around with lorenz system again. I assigned random
> numbers for all the parameters. and made a steady state system based
> on that and solved for the variables. and I get the following. ( the
> code is at the bottom)
>
> {y[0] == 0.1889025652295933*(-1.3382047869208344 -
> 0.47590327034877034*Sqrt[7.906927918602607 -
> 18.515309886236974*e]),
> x[0] == 0.31792235868739005*(1.5727110293983604 +
> 0.5593002876087739*Sqrt[7.906927918602607 -
> 18.515309886236974*e]),
> z[0] == 0.042970475451898735*(7.906927918602607 +
> 2.8119260158479644*Sqrt[7.906927918602607 -
> 18.515309886236974*e]}
>
> What are those little e's at the end of the solutions? Is that euler's
> number? and why can't I use that in NDSolve routine? are those
> signifcant?
>
> any thoughts are appreciated.
>
> In[270]:=
> ode = {x'[t]== -a y[t]-b z[t],y'[t]== c x[t]+d y[t],
> z'[t] == e-f z[t]+f x[t] z[t]}
>
> %/._'[t]->0
>
> Solve[%,{x[t], y[t], z[t]}]
>
> %/.{a-> Random[Real, {1, 3}], b-> Random[Real, {1, 3}],
> c-> Random[Real, {1, 3}],d-> Random[Real, {1, 3}],
> d-> Random[Real, {1, 3}],f-> Random[Real, {1, 3}]}/.Rule ->Equal/.t->
> 0 //InputForm
>
> s1 =% [[1]]
> s2 = %%[[2]]
>
> NDSolve[Join[{x'[t]\[Equal]-a y[t]-b z[t],y'[t]\[Equal]c x[t]+d y[t],
> z'[t]\[Equal]e-f z[t]+f x[t] z[t]}, s1], {x[t], y[t], z[t]}, {t,
> 0, 10}]
>
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