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MathGroup Archive 2004

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Re: solving nonlinear equation with mathematica !!

  • To: mathgroup at smc.vnet.net
  • Subject: [mg47177] Re: solving nonlinear equation with mathematica !!
  • From: Jens-Peer Kuska <kuska at informatik.uni-leipzig.de>
  • Date: Mon, 29 Mar 2004 04:22:24 -0500 (EST)
  • Organization: Universitaet Leipzig
  • References: <c438oj$ekr$1@smc.vnet.net>
  • Reply-to: kuska at informatik.uni-leipzig.de
  • Sender: owner-wri-mathgroup at wolfram.com

Hi,

elim = Eliminate[{x^2 - y - 1 == 0,
10x Exp[-x] - y == 0}, y];

elim = Eliminate[{x^2 - y - 1 == 0,
10x Exp[-x] - y == 0}, y];

{x, x^2 - y - 1 == 0} /. FindRoot[elim, {x, 1}] /. 
  a_Equal :> (y /. Solve[a, y][[1]])

Regards
  Jens

why wrote:
> 
> Hi,
> 
> I face root finding problem solving nonlinear equation
> 
> I have system nonlinear equation
> 
> x^2-y-1 = 0;
> 10x exp(-x)-y = 0 ;
> 
> If you draw the graph you see two intersecting point .
> 
> I have found a point [Using FindRoot function ]
> In (-0.1,-0.5) the point is (-0.0905897,-0.991794 )---it is OK
> 
> But
> In (2.0,1.0) the point is (1.94463,2.7816)
> But the graph says the x->2.something ,y->1.somthing
> I have used same FindRoot function to find the root
> in (2.0,1.0 ).
> 
> Please help me ASAP .
> 
> ..
> I want(exam)to use other methods(bisection/secant etc).
> If any one have workout examples of nonlinear equation
> please let me know .
> .....
> 
> Thank You .


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