Re: Re: Poles and Complex Factoring
- To: mathgroup at smc.vnet.net
- Subject: [mg52106] Re: [mg52097] Re: [mg6011] Poles and Complex Factoring
- From: yehuda ben-shimol <benshimo at bgu.ac.il>
- Date: Thu, 11 Nov 2004 04:52:07 -0500 (EST)
- References: <200411100946.EAA11299@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
Use the GaussianIntegers option Factor[x^2 + 2x + 10, GaussianIntegers -> True] and get ((1 - 3 \[ImaginaryI]) + x) ((1 + 3 \[ImaginaryI]) + x) yehuda bokat wrote: >the complex factoring is wrong > >On 11 Feb 1997 01:29:40 -0500, peter wrote: > > >>Dear All, >> >>I know how to calculate the residue of a fuction using Mathematica, but how >> >> >can I > > >>use Mathematica to calculate the order of a complex pole? >> >>It would also be nice for Mathematica to tell me if a particular singularity >> >> >is an > > >>essential singularity, removable singularity or a pole...but this is >> >> >not > > >>necessary; just icing on the cake. >> >>Also, is there a way to factor polynomials with imaginary roots? >>Something like: >> >> Factor[ x^2 + 2x + 10 ] = (x - 1 + 4.5 I)(x - 1 - 4.5 I) >> >>Much thanks in advance! >> >>Peter >> >>-- >>Birthdays are good for you: A federal funded project has recently >> >> >determined > > >>that people with the most number of birthdays will live the >> >> >longest..... > >
- References:
- Re: Poles and Complex Factoring
- From: bokat02@hotmail.com (bokat)
- Re: Poles and Complex Factoring