Re: Hyperbolic function identity
- To: mathgroup at smc.vnet.net
- Subject: [mg50994] Re: Hyperbolic function identity
- From: mathma18 at hotmail.com (Narasimham G.L.)
- Date: Fri, 1 Oct 2004 04:48:10 -0400 (EDT)
- References: <200409280458.AAA24067@smc.vnet.net> <cjdpr0$aq4$1@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
"Maxim A. Dubinnyi" <maxim at nmr.ru> wrote in message news:<cjdpr0$aq4$1 at smc.vnet.net>... > This works correctly: > FullSimplify[TrigToExp[ArcCosh[1+(z^2)/2]-2*ArcSinh[z/2]], z > 0] > > It looks like that mathematica works better with logarithms and > exponents then with trigonometric functions. Is that one limitation when handling complex functions ? :o(