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Re: Hyperbolic function identity

  • To: mathgroup at
  • Subject: [mg50994] Re: Hyperbolic function identity
  • From: mathma18 at (Narasimham G.L.)
  • Date: Fri, 1 Oct 2004 04:48:10 -0400 (EDT)
  • References: <> <cjdpr0$aq4$>
  • Sender: owner-wri-mathgroup at

"Maxim A. Dubinnyi" <maxim at> wrote in message news:<cjdpr0$aq4$1 at>...
> This works correctly:
> FullSimplify[TrigToExp[ArcCosh[1+(z^2)/2]-2*ArcSinh[z/2]], z > 0]
> It looks like that mathematica works better with logarithms and 
> exponents then with trigonometric functions.

 Is that one limitation when handling complex functions ? :o(

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