Re: Linear Programming

*To*: mathgroup at smc.vnet.net*Subject*: [mg51014] Re: Linear Programming*From*: "Steve Luttrell" <steve_usenet at _removemefirst_luttrell.org.uk>*Date*: Fri, 1 Oct 2004 04:49:33 -0400 (EDT)*References*: <cjgifa$q53$1@smc.vnet.net>*Sender*: owner-wri-mathgroup at wolfram.com

I don't think ConstrainedMin will do what you want. When you use it in Mathematica version 5 you get a message telling you it has been superseded by Minimize. Checking the documentation for ConstrainedMin (http://documents.wolfram.com/v4/RefGuide/ConstrainedMin.html) and for Minimize (http://documents.wolfram.com/v5/Built-inFunctions/AlgebraicComputation/Calculus/Minimize.html) reveals that Minimize does the sort of thing you want. Minimize[x + y, {x > 5, y > 5, 3*x > 5*y, x \[Element] Integers, y \[Element] Integers}, {x, y}] which gives {17, {x -> 11, y -> 6}} It appears that in the current implementation of Minimize you have to constrain y to be integer as well. Steve Luttrell "Rodrigo Malacarne" <malacarne at gmail.com> wrote in message news:cjgifa$q53$1 at smc.vnet.net... > Hi everybody, > > How can I insert a constraint in the following expression > > ConstrainedMin[x+y,{x>5,y>5,3x>5y},{x,y}] > > to find only integer results? Using the expression above I get > > {13.3333,{x->8.3333,y->5.}} > > but I want x to be an integer number. > > Cordially yours, > Rodrigo >