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Re: Problem with Maximize and conditions.
*To*: mathgroup at smc.vnet.net
*Subject*: [mg51068] Re: Problem with Maximize and conditions.
*From*: "Curt Fischer" <crf3 at po.cwru.edu>
*Date*: Sun, 3 Oct 2004 05:47:45 -0400 (EDT)
*References*: <cjlna7$q7f$1@smc.vnet.net>
*Sender*: owner-wri-mathgroup at wolfram.com
Nacho wrote:
[...]
>
> Minimize[{x+y+z, 1/20 x+y+5z\[Equal]100, x \[Element] Integers,
> y \[Element] Integers, z\[Element]Integers, 0<x<99,0<y<99,0<z<99},
> {x,y,
> z}]
>
> I have copied the text using "Plain text" option, I hope it's fine.
>
> This returns the same expression, I suppose that Mathematica cannot
> resolve it. So I use NMinimize:
>
> NMinimize[{x+y+z, 1/20 x+y+5z\[Equal]100, x \[Element] Integers,
> y \[Element] Integers, z\[Element]Integers, 0<x<99,0<y<99,0<z<99},
> {x,y,
> z}]
>
> Now I get a result, but rather weird...
>
> \!\({25.`, {x -> 1, y -> 5, z -> 1899\/100}}\)
>
> The minimum of x+y+z is 25 but z is 1899/100
> 1899/100 is not a Integers, and the nearest Integer, 19, doesn't
> satisfy 1/20x+y+5z==100, and also x+y+z is not 25 but 24.99
[...]
If you multiply the constraint equation by 20, NMinimize [] , but not
Minimize, will get you to the correct answer. I'll leave it for the more
qualified to ponder about why.
In[1]:=
Minimize[{x+y+z,xâ??Integers,yâ??Integers,zâ??Integers,1â?¤x,98â?¥x,1â?¤y,98â?¥y,1â?¤z,98â?¥z,
x+20y+100z\[Equal]2000},{x,y,z}]
Out[1]=
Minimize[{x+y+z,xâ??Integers,yâ??Integers,zâ??Integers,1â?¤x,98â?¥x,1â?¤y,98â?¥y,1â?¤z,98â?¥z,
x+20 y+100 z\[Equal]2000},{x,y,z}]
In[2]:=
NMinimize[{x+y+z,xâ??Integers,yâ??Integers,zâ??Integers,1â?¤x,98â?¥x,1â?¤y,98â?¥y,1â?¤z,98â?¥z
,
x+20y+100z\[Equal]2000},{x,y,z}]
Out[2]=
{43.,{x\[Rule]20,y\[Rule]4,z\[Rule]19}}
--
Curt Fischer
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