       Re: solve and simplify. force left hand side to be 0==

• To: mathgroup at smc.vnet.net
• Subject: [mg51177] Re: [mg51152] solve and simplify. force left hand side to be 0==
• From: "David Park" <djmp at earthlink.net>
• Date: Thu, 7 Oct 2004 05:26:03 -0400 (EDT)
• Sender: owner-wri-mathgroup at wolfram.com

```Sean,

Just Map Simplify to the appropriate level.

sde = {
0 == v1 - d1 e + k2 es - k1 e s,
0 == -k2 es - k3 es + k1 e s,
0 == k3 es - d3 p,
0 == v2 + k2 es - d2 s - k1 e s};
sv = {e, es, p, s};

step1 = Solve[sde[], e][[1, 1]]

sde1 = sde /. step1
Map[Simplify, %, {2}]

David Park

From: sean kim [mailto:sean_incali at yahoo.com]
To: mathgroup at smc.vnet.net

consider a system such as,

sde = {
0==v1-d1 e+k2 es-k1 e s,
0==-k2 es-k3 es+k1 e s,
0==k3 es-d3 p,
0==v2+k2 es-d2 s-k1 e s};

sv = {e,es,p,s};

Solve[sde[], e]

sde1= sde/.%

%//Simplify

shows once I simplify the solution, the structure of
0== stuff... is lost.

is there anyway to force Simplify to keep the
structure so that left hand side is always 0== stuff?

thanks in advance  for any insights.

sean

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