       Re: solve and simplify. force left hand side to be 0==

• To: mathgroup at smc.vnet.net
• Subject: [mg51182] Re: [mg51152] solve and simplify. force left hand side to be 0==
• From: DrBob <drbob at bigfoot.com>
• Date: Thu, 7 Oct 2004 05:26:12 -0400 (EDT)
• References: <200410060834.EAA24236@smc.vnet.net>
• Sender: owner-wri-mathgroup at wolfram.com

```sde = {0 ==
v1 - d1 e[
0] + k2 es - k1 e s, 0 == -k2 es - k3 es[
0] + k1 e s, 0 == k3
es - d3 p, 0 == v2 + k2 es - d2 s - k1 e s};
sde1 = sde /. First@Solve[sde[], e];
0 == HoldForm[Evaluate@Simplify@Last@#] & /@ sde1

Bobby

On Wed, 6 Oct 2004 04:34:39 -0400 (EDT), sean kim <sean_incali at yahoo.com> wrote:

>
> consider a system such as,
>
> sde = {
> 0==v1-d1 e+k2 es-k1 e s,
> 0==-k2 es-k3 es+k1 e s,
> 0==k3 es-d3 p,
> 0==v2+k2 es-d2 s-k1 e s};
>
> sv = {e,es,p,s};
>
> Solve[sde[], e]
>
> sde1= sde/.%
>
> %//Simplify
>
> shows once I simplify the solution, the structure of
> 0== stuff... is lost.
>
> is there anyway to force Simplify to keep the
> structure so that left hand side is always 0== stuff?
>
> thanks in advance  for any insights.
>
>
> sean
>
>
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--
DrBob at bigfoot.com
www.eclecticdreams.net

```

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