Re: Calculus : limits

*To*: mathgroup at smc.vnet.net*Subject*: [mg51340] Re: Calculus : limits*From*: "Dr. Wolfgang Hintze" <weh at snafu.de>*Date*: Thu, 14 Oct 2004 06:38:01 -0400 (EDT)*References*: <ckfs34$isl$1@smc.vnet.net>*Sender*: owner-wri-mathgroup at wolfram.com

Using the option Direction (limit from below/above) solves the problem: In[6]:= Limit[Abs[Sin[x] - Sin[2*x]]/x, x -> 0, Direction -> 1] Out[6]= -1 In[5]:= Limit[Abs[Sin[x] - Sin[2*x]]/x, x -> 0, Direction -> -1] Out[5]= 1 Wolfgang Amir wrote: > Hi, > > I'd like to find the limit of > Limit[(Abs[Sin[x]-Sin[2 x]]) / x, x->0] > > I use Mathematica v.5. I get the wrong (??) answer : 1 > > While I try to display the graph of this function by using "Plot", it > seems that there is no limit at the point x=0. > Please help... > > Amir > >