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MathGroup Archive 2004

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Re: Calculus : limits

  • To: mathgroup at smc.vnet.net
  • Subject: [mg51340] Re: Calculus : limits
  • From: "Dr. Wolfgang Hintze" <weh at snafu.de>
  • Date: Thu, 14 Oct 2004 06:38:01 -0400 (EDT)
  • References: <ckfs34$isl$1@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

Using the option Direction (limit from below/above) solves the problem:

In[6]:=
Limit[Abs[Sin[x] - Sin[2*x]]/x, x -> 0, Direction -> 1]

Out[6]=
-1

In[5]:=
Limit[Abs[Sin[x] - Sin[2*x]]/x, x -> 0, Direction -> -1]

Out[5]=
1

Wolfgang

Amir wrote:

> Hi,
> 
> I'd like to find the limit of
> Limit[(Abs[Sin[x]-Sin[2 x]]) / x, x->0]
> 
> I use Mathematica v.5. I get the wrong (??) answer : 1
> 
> While I try to display the graph of this function by using "Plot", it 
> seems that there is no limit at the point x=0.
> Please help...
> 
> Amir
> 
> 


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