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Re: listplot and plot of the same function display in different scale...

  • To: mathgroup at smc.vnet.net
  • Subject: [mg51658] Re: listplot and plot of the same function display in different scale...
  • From: "Dr. Wolfgang Hintze" <weh at snafu.de>
  • Date: Wed, 27 Oct 2004 23:44:01 -0400 (EDT)
  • References: <clneqo$ocd$1@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

Using objects of the form {x-coord, y-coord} in  ListPlot solves your 
problem.

In[1]:=
solution = NDSolve[{Derivative[1][y][t] == -y[t],
      y[0] == 1}, {y}, {t, 0, 7}];

I added red color to the curve (but even then they can hardly be 
distinguished)

In[15]:=
g0 = Plot[Evaluate[y[t] /. solution], {t, 0, 7},
     PlotStyle -> RGBColor[1, 0, 0], DisplayFunction ->
      Identity];

Notice that I have dropped Flatten and took [[1]] here:

In[8]:=
g1 = ListPlot[Table[{t, Evaluate[y[t] /. solution][[1]]},
      {t, 0, 7, 0.05}], PlotStyle -> PointSize[0.01],
     DisplayFunction -> Identity];


In[16]:=
Show[g0, g1, DisplayFunction -> $DisplayFunction];

Hope this helps.
Wolfgang

sean kim wrote:

> Hello group, 
> 
> let's say you want to take a few points from an
> interploating function and ListPlot it. and then show
> it together with the graph object from Plot. 
> 
> so...
> 
> solution = NDSolve[{y'[t] == -y[t], y[0] == 1}, {y},
> {t, 0, 7}];
> 
> g0 = Plot[Evaluate[y[t] /. solution], {t, 0, 7},
> DisplayFunction -> Identity];
> g1 = ListPlot[Flatten[Table[Evaluate[y[t]/.solution],
> {t, 0, 7, 0.05}]],PlotStyle -> PointSize[0.015],
> DisplayFunction -> Identity];
> 
> Show[g0, g1, DisplayFunction -> $DisplayFunction]
> 
> will show two plots in one graph, but plots have their
> own axis scale. the Plot[] object seems to be shrunk
> in scales due to ListPlot[] object having more points.
> (due to being tabled)
> 
> How do i fix this so that both Plot have same axis
> scales? ( I want to show dots from ListPlot to overlay
> on top of Plot graph. )
> 
> Thanks in advance for any insights. 
> 
> 
> sean 
> 
> 
> 		
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