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Re: ExpandAll Problem with Rules


(a(b + c) -> d(e + f)) // ExpandAll

still gives the error message. It is the use of ExpandAll on Rules that is
the problem.

David Park
djmp at earthlink.net
http://home.earthlink.net/~djmp/

From: Bob Hanlon [mailto:hanlonr at cox.net]
To: mathgroup at smc.vnet.net

Put parentheses around the argument to ExpandAll

(a(b+c)==d(e+f)) // ExpandAll

or use

ExpandAll[a(b+c)==d(e+f)]


Bob Hanlon

>
> From: "David Park" <djmp at earthlink.net>
To: mathgroup at smc.vnet.net
> Date: 2004/09/03 Fri AM 03:35:30 EDT
> To: mathgroup at smc.vnet.net
> Subject: [mg50455] [mg50431] ExpandAll Problem with Rules
>
> The ExpandAll Help says...
>
> ExpandAll[expr] expands out all products and integer powers in any part of
expr.
>
> The following works...
>
> a(b + c) == d(e + f) // ExpandAll
>
> a b + a c == d e + d f
>
> The following appears to work, but gives a strange error message.
>
> a(b + c) -> d(e + f) // ExpandAll
>
> General::argt: ExpandAll called with 0 arguments; 1 or 2 arguments are \
> expected
>
> a b + a c -> d e + d f
>
> David Park
> djmp at earthlink.net
> http://home.earthlink.net/~djmp/
>
>
>
>





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