Re: more than 1 function with Plot3D
- To: mathgroup at smc.vnet.net
- Subject: [mg50843] Re: more than 1 function with Plot3D
- From: mathma18 at hotmail.com (Narasimham G.L.)
- Date: Thu, 23 Sep 2004 05:27:28 -0400 (EDT)
- References: <ci3edp$e2f$1@smc.vnet.net> <cidtco$bt3$1@smc.vnet.net> <cih0lg$mk$1@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
"Ron" <ronhaus at arcor.de> wrote in message news:<cih0lg$mk$1 at smc.vnet.net>... > But the 'Nutzenfunktion" is supposed to be a 3d plot (and not a plane one) > and the other 2d function on that surface. I believe I have to use > ParametricPlot3D combined with Show... You can also 2D plot using different values of constant (instead of 0), for example, NutzFunkt = 120 == (x1 + 20)*x2; > > "Narasimham G.L." <mathma18 at hotmail.com> schrieb im Newsbeitrag > news:cidtco$bt3$1 at smc.vnet.net... > > "Ron" <ronhaus at arcor.de> wrote in message > > news:<ci3edp$e2f$1 at smc.vnet.net>... > >> u(x1,x2) = (x1+20)*x2 (main function) ->Nutzenfunktion > >> 20 = 2x1 + x2 ->Budgetgeraden > >> 60 = 2x2 + x2 ->Budgetgeraden > >> > >> 800 = (x1+20)*x2 -> Indifferenzkurve > > > > Jawohl,moeglich. But with a fresh Kernel.(See other post, Can't get > > graph...) > > > > << Graphics`ImplicitPlot` > > NutzFunkt = 0 == (x1 + 20)*x2; > > BG1 = 20 == 2x1 + x2; > > BG2 = 60 == 2x2 + x1; > > IndiffK = 0 == x2 (x1 + 20) - 800 ; > > VWL = ImplicitPlot[{NutzFunkt, BG1, BG2, IndiffK}, {x1, -100, 100}, > > {x2, -100, > > 100}]; > > Cheers > >