Re: Why can't I call Random[NormalDistribution[10.0,0.0]]?
- To: mathgroup at smc.vnet.net
- Subject: [mg56137] Re: [mg56106] Why can't I call Random[NormalDistribution[10.0,0.0]]?
- From: Mitch.Stonehocker at sungard.com
- Date: Sat, 16 Apr 2005 03:52:44 -0400 (EDT)
- Sender: owner-wri-mathgroup at wolfram.com
Mathematica is giving a correct result
Random[NormalDistribution[?, ?]] /. {? -> 10, ? -> 0}
"NormalDistribution::posscale: The scale parameter 0 is expected to be
positive."
to see this:
PDF[NormalDistribution[?, ?], x] /. ? -> 0
"Indeterminate"
You can always force a result by coding a function to do what you want
but please don't ask Mathematica to.
Cheers,
Mitch Stonehocker
-----Original Message-----
From: barrowes at alum.mit.edu [mailto:barrowes at alum.mit.edu]
To: mathgroup at smc.vnet.net
Subject: [mg56137] [mg56106] Why can't I call
Random[NormalDistribution[10.0,0.0]]?
Why can't I call Random[NormalDistribution[10.0,0.0]]?
I get the error:
NormalDistribution::posscale: The scale parameter 0.` is expected to be
positive.
It seems like I should get a random number with mean 10 and sigma 0. Or
in other words, the result should 10 every time.
In my program I want an array of number taken from different
distributions
Map[Random,Thread[NormalDistribution[Array1,Array2]]]
And elements of Array2 may be 0 for which I woudl ike the corresponding
value in Array1 returned. In fact,
Random[NormalDistribution[10.0,0.000000001]]
does return 10.0 as expected.
This worked in 5.1, but now returns this error in 5.1.1.
Anyone have an easy workaround?
Thanks,
Ben Barrowes