MathGroup Archive 2005

[Date Index] [Thread Index] [Author Index]

Search the Archive

Re: arrange lists side by side


Here is a shorter solution:

In[1]:= a = {28, 30, 17};

In[2]:= b = {1, 2, 9, 4, 5, 7, 3, 8};

In[3]:= MapIndexed[{#1, a[[Mod[#2[[1]], Length[a], 1]]]} &, b]

Out[3]= {{1, 28}, {2, 30}, {9, 17}, {4, 28}, {5, 30}, {7, 17}, {3, 28},
{8, 30}}

Cheers, Vittorio

>-----Original Message-----
>From: marloo3 at mail15.com [mailto:marloo3 at mail15.com]
To: mathgroup at smc.vnet.net
>Sent: Thursday, April 28, 2005 8:41 AM
>Subject: [mg56556] [mg56538] arrange lists side by side
>
>Hi
>is there a way to spread out a small list over a bigger list
recurrently
>like
>this:
>a={28, 30, 17};
>b={1, 2, 9, 4, 5, 7, 3, 8};
>to give the output:
>{{1,28},{2,30},{9,17},{4,28},{5,30},{7,17},{3,28},{8,30}};
>the number of items in "b" do not neccesary  multiples of the number of
>items
>in "a"
>mark
>
>okay this is my approach
>
>a={28,30,17};
>b={1,2,9,4,5,7,3,8};
>aa={};aa=Table[Join[aa,a],{i,Length[b]/Length[a]}]
>
>Out[]=
>{{28,30,17},{28,30,17}}
>
>frc=Mod[Length[b],Length[a]];
>gg=Flatten[Join[aa,Part[a,{1,frc}]]];
>Transpose[Join[{b},{gg}]]
>
>Out[]=
>{{1,28},{2,30},{9,17},{4,28},{5,30},{7,17},{3,28},{8,30}}
>
>----------------------------------------------------------------------
>


  • Prev by Date: Re: arrange lists side by side
  • Next by Date: Re: arrange lists side by side
  • Previous by thread: Re: arrange lists side by side
  • Next by thread: Re: arrange lists side by side