Re: NSolve problem
- To: mathgroup at smc.vnet.net
- Subject: [mg59310] Re: NSolve problem
- From: mike_in_england2000 at yahoo.co.uk
- Date: Fri, 5 Aug 2005 01:21:56 -0400 (EDT)
- References: <dcsc67$q0k$1@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
Hi
Your system of equations has more equations than unkowns (I believe the
term for such a system is over-determined). In such a situation it is
rare for a solution to exist at all. If a solution does exist then one
of the equations is a linear combination of some of the others and so
is reduntant.
In your case the final equation -2 I x + (1 + 3 I) y == 3 + 5 I is a
linear combination of the other two and so you can discard it.
Solve[{2 x + 3 y == 8 + I 7, 3 x + y == 5 + 7 I}]
gives the same solution you had before
{{x -> 1 + 2*I, y -> 2 + I}}
Solve[{2 x + 3 y == 8 + I 7, 3 x + y == 4.9999 + 7 I}]
gives
{{x -> 0.999957142857143 + 2.*I, y -> 2.000028571428571 +
1.0000000000000002*I}}
HTH
Mike