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Re: Questions on Apply function


Out[1] and Out[3] are consistent. In the second argument of In[2], you
are adding b to b1, while in In[1] you are adding b to a1.  The problem
seems to be that your pure function is a function of one variable, but
you are evaluating it with 2 arguments, which means the second argument
will be ignored.  After evaluating Apply, In[1] becomes

{#+{-6750,6435}&[6945,-4545],#+{-6750,6435}&[6945, -4545]}.

Now look at the second argument of the outermost list:  # will assume
the value 6945, the value -4545 will be ignored, and you end up with
the result 6945+{-6750,6435}.  Thus Mathematica will add 6945 to each
number in the list, yielding {195,13380}.

Your comment regarding In[2] suggests that what you really want to do
is:

In[20]:=
Apply[({#1,#2}+{a,b})&,{{a1,b1},{a2,b2},{a3,b3}},{1}]

Out[20]=
{{a+a1,b+b1},{a+a2,b+b2},{a+a3,b+b3}}


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