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MathGroup Archive 2005

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Re: Fourier function...having problems reproducing answers in a paper

  • To: mathgroup at smc.vnet.net
  • Subject: [mg54047] Re: [mg54034] Fourier function...having problems reproducing answers in a paper
  • From: DrBob <drbob at bigfoot.com>
  • Date: Wed, 9 Feb 2005 09:27:18 -0500 (EST)
  • References: <200502081031.FAA17739@smc.vnet.net>
  • Reply-to: drbob at bigfoot.com
  • Sender: owner-wri-mathgroup at wolfram.com

Different FourierParameters explain the difference (read the Help Browser article on Fourier):

Fourier[{0.5, 0, 0.4, 0, 0,
    0.1}, FourierParameters -> {1, -1}]

{1. + 0.*I, 0.35 -
    0.2598076211353316*I,
   0.25 + 0.4330127018922193*I,
   0.8 + 0.*I, 0.25 -
    0.4330127018922193*I,
   0.35 + 0.2598076211353316*I}

Fourier[{0.5, 0, 0.4, 0, 0,
    0.1}, FourierParameters -> {0, 1}]

{0.408248290463863 + 0.*I,
   0.14288690166235204 +
    0.10606601717798214*I,
   0.10206207261596575 -
    0.17677669529663687*I,
   0.32659863237109044 + 0.*I,
   0.10206207261596575 +
    0.17677669529663687*I,
   0.14288690166235204 -
    0.10606601717798214*I}

Bobby

On Tue, 8 Feb 2005 05:31:14 -0500 (EST), elparedblanco <cire1611 at gmail.com> wrote:

> Hi there,
>
> I am using the Fourier function on a simple list probability
> distribution {.5,0,.4,0,0,.1}.  The paper I'm reading says I should be
> geting an answer like this:
>
> {1, .35-.2598i, .25+.433i, .8, .25-.433i, .35+.2598i}.
>
> However this is what Mathematica is returning:
>
> {.408248 + i,  .142887 + .106066i, .102062 - .176777i .326599 + i,
> .102062 + .17677i, .142887 - .106066i }
>
> I assume that these are somehow equivilant.  Can some explain how/why?
>
>
>
>



-- 
DrBob at bigfoot.com
www.eclecticdreams.net


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