Re: Question about an integral

*To*: mathgroup at smc.vnet.net*Subject*: [mg54399] Re: Question about an integral*From*: Peter Pein <petsie at arcor.de>*Date*: Sun, 20 Feb 2005 00:07:57 -0500 (EST)*References*: <cv6ssi$6qb$1@smc.vnet.net>*Sender*: owner-wri-mathgroup at wolfram.com

richard speers wrote: > The previous version of Mathematica integrated 1/x^2 from x=2 to x=A > very nicely, giving 1/2-1/A. The new > version won't do the integral. Please help. > You must not integrate over the origin. So either the real part of A has to be greater than zero or the imaginary part of A must not vanish: Integrate[1/x^2,{x,2,A},Assumptions-> Re[A]>0 || Im[A]!=0] -- Peter Pein Berlin