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Re: Question about an integral


Integrate[1/x^2, {x, 2, a}, GenerateConditions -> False] will let you
see the solution as in previous versions
yehuda


On Sat, 19 Feb 2005 02:32:53 -0500 (EST), richard speers
<rspeers at skidmore.edu> wrote:
> The previous version of Mathematica integrated  1/x^2 from x=2 to x=A
> very nicely, giving 1/2-1/A.  The new
> version won't do the integral.  Please help.
> 
>


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